设函数y=y(x)设函数y=y(x) 由参数方程{x=2et+t+1y=4(t−1)et+t2\begin{cases}x=2e^t+t+1\\y=4(t-1)e^t+t^2\end{cases}确定,则d2ydx2∣t=0=\frac d2y{dx^2}|_{t=0}=______.
23\frac 23
3