曲线(x2+y2)2=x2−y2(x≥0,y≥0)与x轴围成的区域为D,求∬Dxydxdy.\text{曲线}(x^2+y^2)^2=x^2-y^2(x\geq0,y\geq0)\text{与}x\text{轴围成的区域为}D\text{,求}\iint_Dxydxdy.
148\frac{1}{48}
3