记△ABC内角A、B、C的对边分别为a，b，c，已知sinC=2cosB\sin C=\sqrt{2}\cos B，a2+b2−c2=2aba^{2}+b^{2}-c^{2}=\sqrt{2}ab
求B;
若△ABC的面积为3+33+\sqrt{3}，求c.
2